(x^2+3x+2)(x+1)=

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Solution for (x^2+3x+2)(x+1)= equation: 


Simplifying
(x2 + 3x + 2)(x + 1) = 0

Reorder the terms:
(2 + 3x + x2)(x + 1) = 0

Reorder the terms:
(2 + 3x + x2)(1 + x) = 0

Multiply (2 + 3x + x2) * (1 + x)
(2(1 + x) + 3x * (1 + x) + x2(1 + x)) = 0
((1 * 2 + x * 2) + 3x * (1 + x) + x2(1 + x)) = 0
((2 + 2x) + 3x * (1 + x) + x2(1 + x)) = 0
(2 + 2x + (1 * 3x + x * 3x) + x2(1 + x)) = 0
(2 + 2x + (3x + 3x2) + x2(1 + x)) = 0
(2 + 2x + 3x + 3x2 + (1 * x2 + x * x2)) = 0
(2 + 2x + 3x + 3x2 + (1x2 + x3)) = 0

Combine like terms: 2x + 3x = 5x
(2 + 5x + 3x2 + 1x2 + x3) = 0

Combine like terms: 3x2 + 1x2 = 4x2
(2 + 5x + 4x2 + x3) = 0

Solving
2 + 5x + 4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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